16z^2+8z=35

Solution for 16z^2+8z=35 equation:

16z^2+8z=35

We move all terms to the left:

16z^2+8z-(35)=0

a = 16; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·16·(-35)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-48}{2*16}=\frac{-56}{32}
=-1+3/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+48}{2*16}=\frac{40}{32}
=1+1/4
$